(3x-5)^(2)-13(3x-5)+40=0

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Solution for (3x-5)^(2)-13(3x-5)+40=0 equation: 



(3x-5)^(2)-13(3x-5)+40=0

We multiply parentheses

(3x-5)^2-39x+65+40=0

We add all the numbers together, and all the variables

-39x+(3x-5)^2+105=0

We move all terms containing x to the left, all other terms to the right

-39x+(3x-5)^2=-105

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